Simplified Catalase Lab
Question:
Chose one question to investigate:
- What effect will decreasing the substrate (H2O2) concentration by 50% have on the reaction rate?
- What effect will decreasing the enzyme (catalase) concentration by 50% have on the reaction rate?
Background:
"A catalyst ... increases the rate of the [chemical] reaction without being used up in the process. Catalase is an enzyme, a biological (organic) catalyst. Hydrogen peroxide (H2O2) is a poisonous byproduct of metabolism that can damage cells if it is not removed. Catalase is an enzyme that speeds up the breakdown of hydrogen peroxide into H2O and O2." Source: Genevieve Nelson. Access Excellence Catalase Lab. On-line. © The National Health Museum.
We will be using a potato extract as a source of catalase. You will record the time it takes a catalase-soaked paper disk to rise when placed in H2O2. The disk will rise from the added buoyancy of O2 bubbles clinging to it. We will use this time as a proxy measurement for reaction rate.
Hypotheses (predictions):
A prediction using the "If __ then ___, because ____" format is provided by the student.
Equipment:
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Procedure for Measuring Catalase Activity:
Contamination is an issue with this lab. Do not use your fingers. Use the forceps and wash the forceps after touching the catalase or H2O2 solution.
- Fill a test tube with _____ ml of fresh H2O2 solution.
- Use the forceps to place a paper disc in the enzyme solution for _____ seconds.
- Use the forceps to place the disc on a paper towel for ____ seconds to drain off the excess enzyme solution.
- Use the forceps to place the disc at the bottom of the H2O2 solution.
- Measure and record the time it takes the disk to rise to the surface.
- Repeated trails: repeat steps 1 through 5 ______ times.
Procedure for Creating Catalase or Substrate Dilutions:
Student provided.
Data Tables
Student provided.
Conclusions
Student provided.